posted by axl on .
What volume (L) of an aqueous solution that is 24.00 % by mass ammonia (NH3) and has a density of 0.910 g/mL must be taken to obtain 61.2 g of ammonia (NH3) ?
24.00% by mass means
24.00g NH3/100 g soln.
The soln has a density of 0.910; therefore, the volume of the 100 g xoln is 100/0.910 = 109.89 mL so the solution is 24.00g NH3 in 109.89 mL or 0.2184 g/1 mL.
Now 0.2184 g/mL x ??mL = 61.2 g.
Solve for ?? mL.