What volume (L) of an aqueous solution that is 24.00 % by mass ammonia (NH3) and has a density of 0.910 g/mL must be taken to obtain 61.2 g of ammonia (NH3) ?

24.00% by mass means

24.00g NH3/100 g soln.
The soln has a density of 0.910; therefore, the volume of the 100 g xoln is 100/0.910 = 109.89 mL so the solution is 24.00g NH3 in 109.89 mL or 0.2184 g/1 mL.
Now 0.2184 g/mL x ??mL = 61.2 g.
Solve for ?? mL.

To determine the volume of the aqueous solution needed to obtain a certain amount of ammonia (NH3), we need to use the given information about the percentage by mass and density of the solution.

Here are the steps to calculate the volume:

1. Calculate the mass of the solution:
mass = percentage by mass × total mass of solution
mass = 24.00% × total mass of solution

2. Calculate the total mass of the solution:
total mass of solution = mass of ammonia + mass of water

3. Determine the mass of ammonia:
mass of ammonia = 61.2 g

4. Calculate the mass of water:
mass of water = total mass of solution - mass of ammonia

5. Calculate the volume of the solution:
volume = mass / density

Let's plug in the values and calculate each step:

Step 1:
mass = 24.00% × total mass of solution

Step 2:
total mass of solution = mass of ammonia + mass of water

Step 3:
mass of ammonia = 61.2 g

Step 4:
mass of water = total mass of solution - mass of ammonia

Step 5:
volume = mass / density

Please provide the total mass of the solution for me to continue the calculation.