Posted by **Sean ** on Friday, October 1, 2010 at 4:44pm.

A golfer rides in a golf cart at an average speed of 3.10 m/s for 23.0 s. She then gets out of the cart and starts walking at an average speed of 1.30 m/s. For how long (in seconds) must she walk if her average speed for the entire trip, riding and walking, is 2.00 m/s?

- Physics -
**Henry**, Friday, October 1, 2010 at 6:13pm
d1 = 3.1 m/s * 23 s = 71.3 m.

V(ave) = (d1 + d2) / (t1 + t2),

2 = (71.3 + 1.3 * t2) / (23 + t2),

Cross multiply:

46 + 2t2 = 71,3 + 1,3t2,

Solve for t2:

2t2 - 1,3t2 = 71.3 - 46,

0.7t2 = 25.3,

t2 = 36.1 s. = Seconds walked.

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