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May 20, 2013

# Homework Help: Physics Help!

Posted by Kim on Friday, October 1, 2010 at 12:03pm.

A force of 36.1 N is required to start a 4.0 -kg box moving across a horizontal concrete floor. If the 36.1 N force continues, the box accelerates at 0.71 m/s^2. What is the coefficient of kinetic friction?

I got 0.072 as my answer and this is showing as incorrect.

I did:

36.1 - mu x 4.0kg x 9.8 = 4.0kg x 0.71

0.71 / 9.8 = 0.072

• Physics Help! - bobpursley, Friday, October 1, 2010 at 7:36pm

36.1-mu*4*9.8=4*.71
mu=(36.1-4*.71)/(4*9.8)=.85 check that.

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