Homework Help: physics

Posted by vonne on Thursday, September 30, 2010 at 10:52pm.

When you push a 2.05 kg book resting on a tabletop it takes 2.45 N to start the book sliding. Once it is sliding, however, it takes only 1.50 N to keep the book moving with constant speed. What are the coefficients of static and kinetic friction between the book and the tabletop? static? kinetic?

physics - MathMate, Friday, October 1, 2010 at 11:43am
F1 = force to start movement
μs = coefficient of static friction
F2 = force to maintain movement
μk = coefficient of kinetic friction
m = mass

The coefficients of friction are defined as follows:

F1 = μs*mg
F2 = μk*mg

Answer this Question

Related Questions

physics - When you push a 1.70 kg book resting on a tabletop it takes 2.60 N to ...
physics - When you push a 1.70 kg book resting on a tabletop it takes 2.60 N to ...
physics - When you push a 1.55 kg book resting on a tabletop it takes 2.10 N to ...
Physics - When you push a 1.80-kg book resting on a tabletop, it takes 2.05 N to...
Physics - When you push a 1.82-kg book resting on a tabletop, it takes 2.30 N to...
physics - When you push a 1.55 kg block resting on a tabletop it takes 1.85 N to...
phy - When you push a 1.82-{\rm kg} book resting on a tabletop, it takes 2.21 N ...
physics - When you push a 1.95 kg book resting on a tabletop it takes 2.40 N to ...
physics - I keep geting this question wrong and cant figure out what i am doing ...
physics - you push a physics book 1.50m along a horizontal tabletop with a ...

For Further Reading

First Name:
School Subject:
Answer: