A 6.6 nC charge is located 2 m from a 4 nC charge. Find the magnitude of the electrostatic force that one charge exerts on the other.

I already figured it out MYSELF

To find the magnitude of the electrostatic force between two charges, we can use Coulomb's Law. Coulomb's Law states that the electrostatic force between two charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.

Let's consider the given information:
Charge 1 (q1) = 6.6 nC (nanocoulombs)
Charge 2 (q2) = 4 nC (nanocoulombs)
Distance (r) = 2 m (meters)

Now, we can calculate the electrostatic force using the formula:

F = k * (|q1 * q2|) / r^2

Where:
F is the electrostatic force
k is the electrostatic constant, approximately equal to 9 x 10^9 N m^2/C^2
|q1 * q2| is the absolute value of the product of the charges
r^2 is the square of the distance between the charges.

Let's plug in the values:

F = (9 x 10^9 N m^2/C^2) * ((6.6 nC * 4 nC) / (2 m)^2)

To simplify the units, we'll convert nanocoulombs to coulombs:

1 nC = 1 x 10^-9 C

=> F = (9 x 10^9 N m^2/C^2) * ((6.6 x 10^-9 C * 4 x 10^-9 C) / (2 m)^2)

Now, we can calculate the force:

F = (9 x 10^9 N m^2/C^2) * (26.4 x 10^-18 C^2 / 4 m^2)

F = (9 x 10^9 N m^2/C^2) * (6.6 x 10^-18 C^2 / m^2)

F = 59.4 x 10^-9 N

So, the magnitude of the electrostatic force that one charge exerts on the other is approximately 59.4 nanonewtons (nN).