Posted by SAP on Thursday, September 30, 2010 at 10:00pm.
4x+5y=27
x=264y
4(264y) + 5y = 27
104  16y+ 5y = 27
21y =  77
21y = 77
y = 77/31
Now, I’m suppose to return to the 2nd equation x=264y and substitute 77/31 for x, I don’t understand if the is correct way or how to get the answer for the ordered pair.

math need asap  Jen, Thursday, September 30, 2010 at 10:05pm
16y+5y=11y, not 21y..I think that's your mistake

math need asap  Ana Cecilia, Thursday, September 30, 2010 at 10:14pm
the answer is x= 2 and y= 7, this is how its done
4(264y)+5= 27
10416y+5y=27
10411y=27
11y=77
y= 7
then you plug in the y for the next equation
4x+5(7)=27
4x+35=27
4x=8
x=2
and that's how you get your x and y i hope that helped

math need asap  SAP, Thursday, September 30, 2010 at 10:21pm
Ok, so if I use the corrected number you gave, that would make y = 7.
Returning to the 2nd equation x=264y and substituting x for 7.
4y = 7  26
still does not add up, what am I doing wrong?

math need asap  SAP, Thursday, September 30, 2010 at 10:29pm
Ana, thank you, now I understand what I was doing wrong. I couldn't figure out how to rewrite the x=264y equation.
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