A 10 kg box is pulled across the floor at a constant velocity of 3.0 m/s. If the box is pulled with a force of 40 N, what is the size of the frictional force between the box and the floor?
constant velocity? THen the pulling force equals friction.
To find the size of the frictional force between the box and the floor, we can use the equation:
Frictional force (F_friction) = Applied force (F_applied) - Net force (F_net)
We know that the applied force is 40 N and the velocity is constant, which means the net force is zero. Therefore, the frictional force is equal to the applied force.
Hence, the size of the frictional force between the box and the floor is 40 N.
To find the size of the frictional force between the box and the floor, we need to understand the concept of equilibrium. When an object is moving at a constant velocity, the forces acting on it are balanced, resulting in a net force of zero.
In this case, the force of pulling the box with a magnitude of 40 N is acting in one direction. The frictional force between the box and the floor, opposing the motion, is acting in the opposite direction.
Since the box is moving at a constant velocity, the net force on the box is zero. Therefore, the magnitude of the frictional force must be equal to the magnitude of the pulling force, but in the opposite direction.
Therefore, the size of the frictional force between the box and the floor is 40 N.