Physics
posted by Caroline .
A daredevil is shot out of a cannon at 45.0° to the horizontal with an initial speed of 28.0 m/s. A net is positioned a horizontal distance of 51.0 m from the cannon. At what height above the cannon should the net be placed in order to catch the daredevil?

horizontal:
51=28cos45*t solve for t.
Vertical
h=28sin45*t4.9t^2
solve for h. 
9.5

Not gonna tell you the answer directly, but you need to use Trig to find its X & Y velocity. Find the difference between the x axis of the vertex & tramp. Calculate the time according to the horizontal velocity. And take that time multiply it with the gravity