Posted by **Caroline** on Thursday, September 30, 2010 at 8:49pm.

A daredevil is shot out of a cannon at 45.0° to the horizontal with an initial speed of 28.0 m/s. A net is positioned a horizontal distance of 51.0 m from the cannon. At what height above the cannon should the net be placed in order to catch the daredevil?

- Physics -
**bobpursley**, Thursday, September 30, 2010 at 9:32pm
horizontal:

51=28cos45*t solve for t.

Vertical

h=28sin45*t-4.9t^2

solve for h.

- Physics -
**mike**, Monday, October 18, 2010 at 6:09pm
9.5

- Physics -
**Kevin**, Thursday, October 8, 2015 at 10:21am
Not gonna tell you the answer directly, but you need to use Trig to find its X & Y velocity. Find the difference between the x axis of the vertex & tramp. Calculate the time according to the horizontal velocity. And take that time multiply it with the gravity

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