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October 1, 2014

October 1, 2014

Posted by **Jim** on Thursday, September 30, 2010 at 8:44pm.

- Algebra -
**kathryn**, Thursday, September 30, 2010 at 8:59pmI think it would be 1/12.

Each dice has 6 numbers, thus there is a 1/6 probability of rolling any number. When you roll the second dice you have the same probability of getting any number. Since you want the numbers to be the same you would multiple the probabilities of getting one number together. 1/6 x 1/6 = 1/12

- Algebra (correction) -
**PsyDAG**, Friday, October 1, 2010 at 2:47pmFirst of all 1/6 * 1/6 = 1/36 ≠ 1/12

However, the matched pair can be 1s, 2s, 3s, 4s, 5s or 6s. The either-or probability is found by adding the individual probabilities.

1/36 + 1/36 + 1/36 + 1/36 + 1/36 + 1/36 = 6/36 = 1/6

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