each time you breath in, you take in 500 ml of air. the air you breath in is about 20% oxygen by volume. you breath roughly 8 times per minute when you sleep and lets assume you sleep for 8 hours in a night. given this information, how much mass would you lose over the course of 8 hour sleep period as a result of respiring out CO2 through respiration(disregard mass lost due to water loss)
Not enough info. How much CO2 is expelled during a regular breath?
8.0
To calculate the mass lost due to respiration, we need to consider the difference in the percentage of oxygen in the air you inhale and the air you exhale.
Step 1: Calculate the volume of air inhaled in 8 hours of sleep:
500 ml (air inhaled per breath) x 8 breaths per minute x 60 minutes x 8 hours = 1,920,000 ml = 1920 liters
Step 2: Calculate the volume of oxygen inhaled in 8 hours of sleep:
1920 liters (air inhaled) x 0.20 (percentage of oxygen) = 384 liters of oxygen
Step 3: Calculate the volume of carbon dioxide exhaled in 8 hours of sleep:
Carbon dioxide is a byproduct of cellular respiration, and it is estimated that approximately 200 ml of carbon dioxide is exhaled per minute during restful sleep.
200 ml (carbon dioxide exhaled per minute) x 8 breaths per minute x 60 minutes x 8 hours = 76,800 ml = 76.8 liters of carbon dioxide
Step 4: Calculate the mass of carbon dioxide exhaled:
The molar mass of carbon dioxide (CO2) is 44 grams/mole.
76.8 liters (of carbon dioxide) x (1 mole / 22.4 liters) x 44 grams/mole = 144 grams of carbon dioxide
Therefore, over the course of 8 hours of sleep, you would lose approximately 144 grams of mass through respiration by exhaling carbon dioxide.