Posted by Thalia on Thursday, September 30, 2010 at 4:20pm.
equation of the tangent line is y-f(a)=f'(a)(x-a)
in this case i am assuming your a=1 so your f(1)=8
to find f'(a) plug 1 into your derivative , It will be 2
y-8=2(x-1)
now solve for y
y=2x-2+8
y=2x+6 <-- y=mx+b form.
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