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Posted by on Thursday, September 30, 2010 at 4:20pm.

supose that (f(x+h)-f(x))/h=3x^2-6h+5 and f(1)=8. ind the equation of the tangent line to the graph of y=f(x) at x=1. if we write this equation in the form y=mx+b then m=? and b=?

  • calculus - , Thursday, September 30, 2010 at 11:32pm

    equation of the tangent line is y-f(a)=f'(a)(x-a)

    in this case i am assuming your a=1 so your f(1)=8

    to find f'(a) plug 1 into your derivative , It will be 2
    y-8=2(x-1)
    now solve for y
    y=2x-2+8
    y=2x+6 <-- y=mx+b form.

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