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July 30, 2014

July 30, 2014

Posted by **Thalia** on Thursday, September 30, 2010 at 4:20pm.

- calculus -
**rafay**, Thursday, September 30, 2010 at 11:32pmequation of the tangent line is y-f(a)=f'(a)(x-a)

in this case i am assuming your a=1 so your f(1)=8

to find f'(a) plug 1 into your derivative , It will be 2

y-8=2(x-1)

now solve for y

y=2x-2+8

y=2x+6 <-- y=mx+b form.

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