Posted by **laura** on Thursday, September 30, 2010 at 3:09pm.

In a historical movie, two knights on horseback start from rest 91 m apart and ride directly toward each other to do battle. Sir George's acceleration has a magnitude of 0.18 m/s2, while Sir Alfred's has a magnitude of 0.33 m/s2. Relative to Sir George's starting point, where do the knights collide?

- physics -
**MathMate**, Thursday, September 30, 2010 at 5:43pm
use

u=initial velocity=0 m/s

a=acceleration, m/s²

t=time in seconds

Distance S = ut+(1/2)at² m

for each knight.

The sum of the distances is 91 m.

Solve for t and hence the distances travelled by each.

- physics -
**Sean**, Friday, October 1, 2010 at 6:53pm
i still don't understand how to write this equation

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