Saturday

September 20, 2014

September 20, 2014

Posted by **mike** on Thursday, September 30, 2010 at 2:02pm.

PLEASE EXPLAIN IM LOST

- calculus -
**Sarah**, Monday, November 29, 2010 at 5:27amYou use the quotient rule of :[u'v -uv']/v^2

so:

u=(6x+1) v=(19x+1)^1/2

u'=6 v'= [1/2(19x+1)^-1/2] (19)

y' = 6[(19x+1)^1/2] - (6x+1)[1/2(19x+1)^-1/2] (19)

you can simplify it by taking a common factor. In this case its easier to take (19x+1)^-1/2--- Always take the lowest common factor.

y'=[[19x+1]^-1/2] 6(19x+1) -(6x+1)(1/2)(19)

y'=[[19x+1]^-1/2] 114x+6-57x+9.5

Final answer:

y'=[[19x+1]^-1/2] 57x + 15.5

**Answer this Question**

**Related Questions**

Calculus-Mean Value Theorem - Find the function G(x) whose graph passes through...

Calculus - Use a symbolic differentiation utility to find the derivative of the ...

Calc - a) y =ln(x-1) find dy/dx=? b) y=3 ln x - ln (1/x) where x >0, dy/dx...

calculus - Find the length of the arc formed by y = (1/8)(4x^2-2ln(x)) from x=4 ...

Calculus 1 - Could you please explain how to find the slope using the definition...

Calculus - Find the interval(s) where the function is increasing and the ...

Calculus - Given the function: f(x) = x^2 + 1 / x^2 - 9 a)find y and x ...

calculus - Find the derivative of the function. y=cos((1-e^x)/(1+e^x)) Please ...

Calculus - Given the function: f(x) = x^2 + 1 / x^2 - 9 a)find y and x ...

Calculus - Given the function: f(x) = x^2 + 1 / x^2 - 9 a)find y and x ...