Posted by **danielle** on Thursday, September 30, 2010 at 11:07am.

If a car starts from rest and accelerates at 6.0 m/sec2 for 6.0 seconds. how far did it travel and how fast was it moving at the end of the 6.0 seconds

- physics -
**Lost In Studies**, Thursday, September 30, 2010 at 2:35pm
Assemble the data first:

Initial velocity = vi = 0m/s

Acceleration = a = 6m/s2

Time = t = 6s

Distance = S = ??

Final velocity = vf = ??

Now using equations of motion:

FOR DISTANCE:

Since,

S = vit + 1/2at2

Put in the values,

S = 0*6 + 1/2*6*(6)2

S = 0 + 1/2*6*36

S - 108m

FOR FINAL VELOCITY

Both remaining equations of motion can be used.

Method # 01:

Using equation;

2aS = vf2 - vi2

2*6*108 = vf2-0

1296 = vf2

vf2 = 1296

vf = square root of 1296

vf = 36m/s

OR

Methos # 02:

Using equation;

vf = vi + at

vf = 0 + 6*6

vf = 36m/s.

Hope it helps.

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