Posted by danielle on Thursday, September 30, 2010 at 11:07am.
If a car starts from rest and accelerates at 6.0 m/sec2 for 6.0 seconds. how far did it travel and how fast was it moving at the end of the 6.0 seconds

physics  Lost In Studies, Thursday, September 30, 2010 at 2:35pm
Assemble the data first:
Initial velocity = vi = 0m/s
Acceleration = a = 6m/s2
Time = t = 6s
Distance = S = ??
Final velocity = vf = ??
Now using equations of motion:
FOR DISTANCE:
Since,
S = vit + 1/2at2
Put in the values,
S = 0*6 + 1/2*6*(6)2
S = 0 + 1/2*6*36
S  108m
FOR FINAL VELOCITY
Both remaining equations of motion can be used.
Method # 01:
Using equation;
2aS = vf2  vi2
2*6*108 = vf20
1296 = vf2
vf2 = 1296
vf = square root of 1296
vf = 36m/s
OR
Methos # 02:
Using equation;
vf = vi + at
vf = 0 + 6*6
vf = 36m/s.
Hope it helps.
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