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physics

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If a car starts from rest and accelerates at 6.0 m/sec2 for 6.0 seconds. how far did it travel and how fast was it moving at the end of the 6.0 seconds

  • physics - ,

    Assemble the data first:

    Initial velocity = vi = 0m/s
    Acceleration = a = 6m/s2
    Time = t = 6s
    Distance = S = ??
    Final velocity = vf = ??

    Now using equations of motion:

    FOR DISTANCE:

    Since,
    S = vit + 1/2at2
    Put in the values,

    S = 0*6 + 1/2*6*(6)2
    S = 0 + 1/2*6*36
    S - 108m

    FOR FINAL VELOCITY

    Both remaining equations of motion can be used.

    Method # 01:

    Using equation;
    2aS = vf2 - vi2
    2*6*108 = vf2-0
    1296 = vf2
    vf2 = 1296
    vf = square root of 1296
    vf = 36m/s

    OR

    Methos # 02:

    Using equation;
    vf = vi + at
    vf = 0 + 6*6
    vf = 36m/s.

    Hope it helps.

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