physics
posted by danielle on .
If a car starts from rest and accelerates at 6.0 m/sec2 for 6.0 seconds. how far did it travel and how fast was it moving at the end of the 6.0 seconds

Assemble the data first:
Initial velocity = vi = 0m/s
Acceleration = a = 6m/s2
Time = t = 6s
Distance = S = ??
Final velocity = vf = ??
Now using equations of motion:
FOR DISTANCE:
Since,
S = vit + 1/2at2
Put in the values,
S = 0*6 + 1/2*6*(6)2
S = 0 + 1/2*6*36
S  108m
FOR FINAL VELOCITY
Both remaining equations of motion can be used.
Method # 01:
Using equation;
2aS = vf2  vi2
2*6*108 = vf20
1296 = vf2
vf2 = 1296
vf = square root of 1296
vf = 36m/s
OR
Methos # 02:
Using equation;
vf = vi + at
vf = 0 + 6*6
vf = 36m/s.
Hope it helps.