Wednesday
September 17, 2014

Homework Help: Algebra 2

Posted by Anonymous on Wednesday, September 29, 2010 at 11:09pm.

Is this how you solve t(t+1)(t+2)=0, x^3+4x=4x^2, and 3r^2=4r-1?

t(t+1)(t+2)=0
t=0 or t= -1 or t=2
{0, -1, -2}

x^3+4x=4x^2
x^3+4x-4x^2=0
x(x^2+4-4x)=0
x(x^2-4x+4)=0
x(x-2)(x-2)=0
x=0 or x=2
{0,2(double root)}

3r^2=4r-1
3r^2-4r+1=0
r^2-4r+3=0
(r-3)(r-1)=0
r=3 or r=1
{1,3}

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