Posted by Hayli on Wednesday, September 29, 2010 at 9:50pm.
Use a normal approximation to the binomial distribution.
Your values are the following:
p = .52, q = 1 - p = .48, x = 1, and n = 3
Find mean and standard deviation.
mean = np = (3)(.52) = ?
sd = √npq = √(3)(.52)(.48) = ?
I'll let you finish the calculations.
Once you have the mean and standard deviation, use z-scores and z-table to find probability.
P(0.5 < x < 1.5) =
P[(0.5 - mean)/sd] < z < [(1.5 - mean)/sd]
Once you have the two z-scores (substitute the mean and sd calculated), find the difference between the two using a z-table. This will be your probability.
I hope this will help get you started.
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