Post a New Question

Math

posted by .

Find each specified function value:
What am I doing wrong because the correct answer for (a) is 3 and (b) is
-t^3/4-5t^2/4-t+3

Here's the problem: P(x)=2x^3-5x^2+2x+3
(a) P(0) 2(0)^3-5(0)^2+2(0)^3
2-5+3 my answer I get O

(b) Here's the problem P(x)=2x^3-5x^2+2+3
P (-1/2 t)
2(-1/2t)^3-5(-1/2)^2+2(-1/2)+3
2(-1/8)-5(1/4)-1+3 my answer 1/2

  • Math -

    a. The 1st 3 terms are = to zero,because you multiplied each coefficient by zero. Where you have 2 - 5 +3 = 0, the 5 and the 2 should be zeroes.

    P(0) = 0 + 0 + 0 + 3 = 3.

Answer This Question

First Name
School Subject
Your Answer

Related Questions

More Related Questions

Post a New Question