Posted by Heather on Wednesday, September 29, 2010 at 4:19pm.
Find each specified function value:
What am I doing wrong because the correct answer for (a) is 3 and (b) is
t^3/45t^2/4t+3
Here's the problem: P(x)=2x^35x^2+2x+3
(a) P(0) 2(0)^35(0)^2+2(0)^3
25+3 my answer I get O
(b) Here's the problem P(x)=2x^35x^2+2+3
P (1/2 t)
2(1/2t)^35(1/2)^2+2(1/2)+3
2(1/8)5(1/4)1+3 my answer 1/2

Math  Henry, Wednesday, September 29, 2010 at 5:03pm
a. The 1st 3 terms are = to zero,because you multiplied each coefficient by zero. Where you have 2  5 +3 = 0, the 5 and the 2 should be zeroes.
P(0) = 0 + 0 + 0 + 3 = 3.