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February 1, 2015

February 1, 2015

Posted by **Heather** on Wednesday, September 29, 2010 at 4:19pm.

What am I doing wrong because the correct answer for (a) is 3 and (b) is

-t^3/4-5t^2/4-t+3

Here's the problem: P(x)=2x^3-5x^2+2x+3

(a) P(0) 2(0)^3-5(0)^2+2(0)^3

2-5+3 my answer I get O

(b) Here's the problem P(x)=2x^3-5x^2+2+3

P (-1/2 t)

2(-1/2t)^3-5(-1/2)^2+2(-1/2)+3

2(-1/8)-5(1/4)-1+3 my answer 1/2

- Math -
**Henry**, Wednesday, September 29, 2010 at 5:03pma. The 1st 3 terms are = to zero,because you multiplied each coefficient by zero. Where you have 2 - 5 +3 = 0, the 5 and the 2 should be zeroes.

P(0) = 0 + 0 + 0 + 3 = 3.

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