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2nd time posting bc i still need HELP! PHYSICS!!!!

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The velocity of a diver just before hitting the water is -8.6 m/s, where the minus sign indicates that her motion is directly downward. What is her displacement during the last 0.86 s of the dive?

im so stuck. i tried this problem several times, and my answers werent correct. please help me.

  • 2nd time posting bc i still need HELP! PHYSICS!!!! -

    I had a problem similar to this but I was using -11.4 m/s and 1.35 s. You can use my calculations below and just plug in your numbers.


    Velocity of diver just before hitting the water,Vf = - 11.4 m/s

    Time, t = 1.35 s

    Velocity of diver before 1.35 s = Vi

    Vf = Vi - g t

    - 11.4 = Vi - 9.8 * 1.35

    - 11.4 = Vi - 13.23

    Vi = 13.23 - 11.4

    = 1.83 m/s

    Displacement during 't' s , S = [ ( Vi + Vf ) /2 ] t

    = [ ( 1.83 - 11.4 ) / 2 ] * 1.35

    = - 6.46 m

  • 2nd time posting bc i still need HELP! PHYSICS!!!! -

    Vf=Vo+gt where Vf is velocity just before hitting water, and Vo is at the start of the .86
    -8.6m/s=Vo-9.8(-.86)
    Vo= -8.6+8.43=-.172

    So the average velocity is 8.49, displacement then is downward 8.49*.86 meters

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