Posted by ibo on Wednesday, September 29, 2010 at 2:52pm.
make a diagram.
you should have a right-angled triangle, where the angle of elevation is Ø, the adjacent is 100 and the opposite is h, the height of the rocket.
tanØ = h/100
h = 100tanØ
dh/dt = 100sec^2 Ø (dØ/dt)
when Ø = 60° or π/3 rad
dØ/dt = 12°/sec or 12π/180 rad/sec = π/15 rad/sec
sub into the dh/dt equation and you are done
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