Posted by **ibo** on Wednesday, September 29, 2010 at 2:51pm.

The equation x^2 y+2xy^3=8defines y as a function of x,y=f(x), near x=2, y=1.

a) Find dy/dx.

b) Now, find the slope of the curve

x^2y+2xy^3=8 when x=2, y=1.

- calculus -
**Reiny**, Wednesday, September 29, 2010 at 4:51pm
differentiate implicitly,

x^2 + 2xy^3 = 8

2x + 2x(3y^2)dy/dx + 2(y^3) = 0

solve for dy/dx, then for b) sub in x=2, y=1

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