calculus
posted by sam on .
A boat is pulled into a dock by a string attached to the bow of the boat and passing through a pulley on the dock that is1ft higher than the bow of the boat. If the string is pulled at a rate of 3 ft/second, how fast is the boat approaching the dock when it is 7 ft from the dock?

Make a diagram, you should have a rightangled triangle.
let the horizontal distance of the boat from the dock be x ft
let the hypotenuse, the length of the rope, be y ft.
then x^2 + 1^2 = y^2
2xdx/dt = 2ydy/dt
when x=7
y^2 = 7^2 + 1^ = 50
y = √50
and you are given dy/dt = 3 ft/s (I made it negative since y is decreasing)
sub in and you are on your way.