Posted by **Anonymous** on Wednesday, September 29, 2010 at 2:07pm.

A hockey puck struck by a hockey stick is given an initial speed v0 in the positive x-direction. The coefficient of kinetic friction between the ice and the puck is μk.

(a) Obtain an expression for the acceleration of the puck. (Use the following as necessary: μk and g.)

a =

(b) Use the result of part (a) to obtain an expression for the distance d the puck slides. The answer should be in terms of the variables v0, μk, and g only.

d =

- Physics -
**Dan**, Sunday, January 10, 2016 at 12:08am
f = ma

μk * f(normal) = m*a

μk *m*g = m*a

μk *g =a

so a = μk*g

this is defined to be a negative acceleration since the friction force works in the opposite direction to the movement of the puck

vFinal = v0 + at

so t = (vF-v0)/a

d = t*(vF+v0)/2

so d = (vF+v0)(vF-v0)/2a

substitute in our 'known' values: a = μk*g, and vF = 0 (since the puck has stopped sliding)

d = (0+v0)(0-v0)/ 2(μk*g)

d = v0^2 / (2μk*g)

(eliminate negatives as d is positive)

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