Solve by completing the square x2 - 2x - 5 = 0. Help please
a)1 plus or minus√6
b)-1 plus or minus√6
c)-3 plus or minus 2√6
d)3 plus or minus 2√6
x^2-2x + ...=5
half of -2,then square it.
x^2-2x+1=5+1
(x-1)^2=(sqrt6)^2
you finish.
i don't know how?(:<
(x-1)^2=sqrt6^2
Take the square root of both sides.
x-1=sqrt6..
you have to know how to finish from here
To solve the given quadratic equation x^2 - 2x - 5 = 0 by completing the square, follow these steps:
Step 1: Move the constant term to the other side of the equation
x^2 - 2x = 5
Step 2: Take half of the coefficient of x, square it, and add it to both sides of the equation
To find half of the coefficient of x: (-2)/2 = -1
(-1)^2 = 1
x^2 - 2x + 1 = 5 + 1
x^2 - 2x + 1 = 6
Step 3: Rewrite the left side of the equation as a perfect square
(x - 1)^2 = 6
Step 4: Solve for x by taking the square root of both sides
√(x - 1)^2 = ±√6
(x - 1) = ±√6
Step 5: Solve for x by adding 1 to both sides
x = 1 ± √6
Thus, the solutions to the quadratic equation x^2 - 2x - 5 = 0 are:
x = 1 + √6 or x = 1 - √6
So the correct answer is:
a) 1 plus or minus √6