If 920 mL of 0.0402 M aqueous LiOH reacts stoichiometrically according to the balanced equation, what mass (g) of gaseous CO2 is required?

Question

If 920 mL of 0.0402 M aqueous LiOH reacts stoichiometrically according to the balanced equation, what mass (g) of gaseous CO2 is required?

2 LiOH(aq) + CO2(g) → Li2CO3(aq)

Answer 1

molarity(M)=mol/L

or mol=(M)(L)

be sure to convert 920mL to L!

convert mol of LiOH to mol of CO2 by mole ratio (coefficients of balanced equation)

multiply by CO2 molar mass to get mass(g) of gaseous CO2