Thursday
July 31, 2014

Homework Help: Chemistry

Posted by Jeremy on Tuesday, September 28, 2010 at 11:19pm.

Hi, I posted my question earlier but I was having some difficulty with it.
2Al+ 3Cl2-->2AlCl3
You are given 31.0g of aluminum and 36.0g of chlorine gas.

1.If you had excess chlorine, how many moles of aluminum chloride could be produced from 31.0g of aluminum?

_________________________________________
This is my work so far:

Cl2-36.0g/70.9= 0.507mol
Al-31.0g/26.98=1.15mol

Therefore Chlorine is the limiting reagent, since I have less that 3/2.

Cl2:AlCl3= 3:2
0.507mol (3/2)=0.76 mol AlCl3.

Please check my answer and significant figures. I am pretty sure I messed up!

Answer this Question

First Name:
School Subject:
Answer:

Related Questions

CHEM - Aluminum reacts with chlorine gas to form aluminum chloride via the ...
Chemistry - 2Al(s)+3Cl2 = 2AlCl3 Limiting Reactant is Cl with 0.329mol. What is...
CHEM-last part prob. - Aluminum reacts with chlorine gas to form aluminum ...
Chemistry - Please help solve; 2Al +3Cl2 --> 2AlCl3 You are give 31.0g Al and...
CHEM - Aluminum reacts with Chlorine gas to form AlCl3. [2Al(s)+3Cl2(g)=2AlCl3(s...
chemistry-Chemical Formulas And Reactions - What is the balaced equation for the...
chemistry! - how many moles of product are formed in the reaction? 2Al(s),3Cl2(g...
chemistry - Aluminum reacts with hydrochloric acid to produce aluminum chloride ...
chemistry - You are given 28.0 of aluminum and 33.0 of chlorine gas. Part A If ...
Chemistry - For the reaction shown, compute the theoretical yield of the product...

Search
Members