Thursday
April 24, 2014

Homework Help: Chemistry

Posted by Jeremy on Tuesday, September 28, 2010 at 11:19pm.

Hi, I posted my question earlier but I was having some difficulty with it.
2Al+ 3Cl2-->2AlCl3
You are given 31.0g of aluminum and 36.0g of chlorine gas.

1.If you had excess chlorine, how many moles of aluminum chloride could be produced from 31.0g of aluminum?

_________________________________________
This is my work so far:

Cl2-36.0g/70.9= 0.507mol
Al-31.0g/26.98=1.15mol

Therefore Chlorine is the limiting reagent, since I have less that 3/2.

Cl2:AlCl3= 3:2
0.507mol (3/2)=0.76 mol AlCl3.

Please check my answer and significant figures. I am pretty sure I messed up!

Answer this Question

First Name:
School Subject:
Answer:

Related Questions

Chemistry - Please help solve; 2Al +3Cl2 --> 2AlCl3 You are give 31.0g Al and...
CHEM - Aluminum reacts with chlorine gas to form aluminum chloride via the ...
CHEM-last part prob. - Aluminum reacts with chlorine gas to form aluminum ...
Chemistry - 2Al(s)+3Cl2 = 2AlCl3 Limiting Reactant is Cl with 0.329mol. What is...
CHEM - Aluminum reacts with Chlorine gas to form AlCl3. [2Al(s)+3Cl2(g)=2AlCl3(s...
Chemistry - Aluminum and chlorine gas react together to make Aluminum chloride. ...
Chemistry - What is the maximum mass of aluminum chloride that can be formed ...
chemistry-Chemical Formulas And Reactions - What is the balaced equation for the...
College Chemistry - 25.0g of aluminum reacts with 55.0grams of chlorine gas to ...
chemistry-stoichiometry - how many grams of chlorine can be liberated from the ...

Search
Members