Saturday

December 20, 2014

December 20, 2014

Posted by **Natalie** on Tuesday, September 28, 2010 at 11:11pm.

- calculus -
**WaywardSon**, Tuesday, September 28, 2010 at 11:26pm2x+10y=23 (is what im guessing since the problem breaks awkwardly there)

y=-1/5x+23/10 (slope intercept form)

derivative of y=x^2+14x (im guessing since it looks like you expressed it wrong)

y'=2x+14

I'll leave it up to you at that point.

- calculus -
**Natalie**, Tuesday, September 28, 2010 at 11:34pmYes. Sorry.

I did get it up to the derivative of y' = 2x + 14 by using the

f'(x) = [f(x+h) - f(x)] / h

formula.

and did simplify the other equation into the slope-intercept form.

but do I just plug the derivative into the 'slope-intercept' equation?

because isn't y' = 2x+14 the slope of the tangent.

I guess I'm mostly confused because I need to find a point parallel to that second equation and for the point to be parallel, they must have the same slope.

yet the derivative gave me a different slope?

- calculus -
**MathMate**, Tuesday, September 28, 2010 at 11:44pmFor slope intercept form,

y=mx+b

m is the slope.

You need to find the value of x for which

f'(x)=m, i.e. tangent parallel to y=mx+b.

- calculus -
**WaywardSon**, Tuesday, September 28, 2010 at 11:45pmA slope can't be an equation. It's a number, and your solving for x so that the equation equals the slope of the line.

Also your teacher taught you the long way of doing a derivative, if the "Power Rule" for derivatives never comes up in class you're better off looking it up yourself.

- calculus -
**Natalie**, Tuesday, September 28, 2010 at 11:52pmI'm sorry. For the life of me, I just can't figure out this problem.

Okay, so if the slope can't be an equation, can i solve for x by setting y' equal to zero?

or do you mean

2x + 14 = (-1/5) x + (23/10)

I tried both ways I just listed, and they turned out wrong, so I'm still lost.

He did teach us the shortcut during my last class. It was just a force of habit to do it the long way.

Thank you so much for helping me.

- calculus -
**Natalie**, Tuesday, September 28, 2010 at 11:57pmI've also just tried:

-1/5 = 2x + 14

x = -.568

and plugged that into the 'parallel' equation to solve for y.

y= 2.4136

but that still didn't work out.

- calculus -
**RePost**, Tuesday, September 28, 2010 at 11:57pmwhat's the slope of the line?

set 2x+14 equal to that and solve.

(hint:slope intercept form y=mx+b)

sorry if i sound like a twat but trust me that you'll remember things better if you figure them out yourself.

- calculus -
**WaywardSon**, Wednesday, September 29, 2010 at 12:00amhow on earth did you get x=-.568

the equation is right you just solved it wrong.

- calculus -
**Natalie**, Wednesday, September 29, 2010 at 12:00amOkay. My bad.

I'm sorry all, I apparently can't do basic math.

Thank you everyone for helping me.

I really appreciated it.

- calculus -
**WaywardSon**, Wednesday, September 29, 2010 at 12:03amx=-7.1

- calculus -
**Natalie**, Wednesday, September 29, 2010 at 12:17amAlright. One last question.

So I'm wondering if my online homework answer is wrong, because I have x and I've plugged x back into the y = (-1/5)x + (23/10)

and I've solved for y.

y = 3.72

Now please tell me if I'm just making a fool of myself again and am incorrectly solving an algebraic equation or is it wrong, because it won't accept 3.72 as the y, but accepts -7.1 as the x.

- calculus -
**WaywardSon**, Wednesday, September 29, 2010 at 12:28amyou don't plug it into the equation of the line.

what you are trying to do is to get the derivative equal to the slope of the line y=-1/5x+23/10

y=mx+b

so the slope, m=(-1/5)

therefore -1/5=2x+14

where x=(-7.1)

check your solution

y=2(-7.1)+14=-.2 (or -1/5)

- calculus -
**Reiny**, Wednesday, September 29, 2010 at 12:33ammy oh my oh my !!!

why did you not follow MathMate's idea?

y' = 2x + 14, that is your slope at any point (x,y)

the slope of the given straight line is -1/5

so 2x + 14 = -1/5

x = 7.1 You had that!

then y = (7.1)^2 + 14(7.1) = 149.81

so the point of contact is (7.1, 149.81)

since the new line is parallel to the old, it must have the same x and y terms, so

2x + 10y = c

plug in the point

2(7.1) + 10(149.81) = c = 1512.3

equation:

2x + 10y = 1512.3

- calculus -
**WaywardSon**, Wednesday, September 29, 2010 at 12:34amderivative is a slope. so y'=..... is not the same as y=.....

think of y' as m, a slope as well but tangent to graph.

- calculus -
**RePost**, Wednesday, September 29, 2010 at 12:38am>Reiny

spoon fed the answer right there, so yeah never plug it in to the equation of the line.

- calculus -
**Natalie**, Wednesday, September 29, 2010 at 12:42amWow thank you guys all so much.

I'm dreading a whole semester of calculus.

(stats was so much easier)

Thanks especially for explaining everything, so now I understand it.

**Answer this Question**

**Related Questions**

calculus - Consider the curve defined by 2y^3+6X^2(y)- 12x^2 +6y=1 . a. Show ...

12th Grade Calculus - 1. a.) Find an equation for the line perpendicular to the ...

calculus - A curve passes through the point (1,-11) and it's gradient at any ...

Calculus - Consider the curve y^2+xy+x^2=15. What is dy/dx? Find the two points ...

calculus - 1. Given the curve a. Find an expression for the slope of the curve ...

calculus - Consider line segments which are tangent to a point on the right half...

Calculus - Please help this is due tomorrow and I dont know how to Ive missed a ...

Help Calc.! - original curve: 2y^3+6(x^2)y-12x^2+6y=1 dy/dx=(4x-2xy)/(x^2+y^2+1...

please help; calc - original curve: 2y^3+6(x^2)y-12x^2+6y=1 dy/dx=(4x-2xy)/(x^2+...

Calculus - Consider line segments which are tangent to a point on the right ...