The velocity of a diver just before hitting the water is -8.6 m/s, where the minus sign indicates that her motion is directly downward. What is her displacement during the last 0.86 s of the dive?
im so stuck. i tried this problem several times, and my answers werent correct. please help me.
To solve this problem, you can use the equation for displacement:
displacement = (initial velocity * time) + (0.5 * acceleration * time^2)
In this case, the initial velocity is -8.6 m/s (negative indicating downward motion), and the time is 0.86 s.
The displacement equation becomes:
displacement = (-8.6 m/s) * (0.86 s) + (0.5 * acceleration * (0.86 s)^2)
To find the acceleration, you need to know if there is a net force acting on the diver while she is falling. If there is no force other than gravity, the acceleration would be the acceleration due to gravity (approximately 9.8 m/s^2).
Let's assume that the acceleration due to gravity is involved in this problem. Plug in the values:
displacement = (-8.6 m/s) * (0.86 s) + (0.5 * 9.8 m/s^2 * (0.86 s)^2)
Now, calculate the final answer:
displacement = -7.396 + 3.7748
displacement ≈ -3.6212 m
The displacement during the last 0.86 s of the dive is approximately -3.6212 meters. The negative sign indicates a downward displacement.