college algebra
posted by lee .
The length of a carpet is 5 Ft. more than the width. The perimeter is 34 ft. What is the area?

34=2l+2w = 2(w5)+2w
solve for w, then l, then l*w
posted by lee .
The length of a carpet is 5 Ft. more than the width. The perimeter is 34 ft. What is the area?
34=2l+2w = 2(w5)+2w
solve for w, then l, then l*w