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Posted by on Tuesday, September 28, 2010 at 8:55pm.

Is this how you solve t^3 - t = 0?

t(t^2-1)=0
t(t-1)(t-1)=0
t=0 or t=1
{0,1}

  • Algebra 2 - , Tuesday, September 28, 2010 at 8:57pm

    no, t(t+1)(t-1)=0
    now solve.

  • Algebra 2 - , Tuesday, September 28, 2010 at 9:02pm

    so t=0 or t=-1 or t=1, and the solution set is {0,-1,1}?

  • Algebra 2 - , Tuesday, September 28, 2010 at 9:07pm

    yes.

  • Algebra 2 - , Tuesday, September 28, 2010 at 9:24pm

    thanks

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