Posted by **Danny123** on Tuesday, September 28, 2010 at 8:55pm.

Is this how you solve t^3 - t = 0?

t(t^2-1)=0

t(t-1)(t-1)=0

t=0 or t=1

{0,1}

- Algebra 2 -
**bobpursley**, Tuesday, September 28, 2010 at 8:57pm
no, t(t+1)(t-1)=0

now solve.

- Algebra 2 -
**Danny123**, Tuesday, September 28, 2010 at 9:02pm
so t=0 or t=-1 or t=1, and the solution set is {0,-1,1}?

- Algebra 2 -
**bobpursley**, Tuesday, September 28, 2010 at 9:07pm
yes.

- Algebra 2 -
**Danny123**, Tuesday, September 28, 2010 at 9:24pm
thanks

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