Is this how you solve t^3 - t = 0?

t(t^2-1)=0
t(t-1)(t-1)=0
t=0 or t=1
{0,1}

no, t(t+1)(t-1)=0

now solve.

so t=0 or t=-1 or t=1, and the solution set is {0,-1,1}?

yes.

thanks

Yes, your approach is correct. To solve the equation t^3 - t = 0, you factored it as t(t^2-1)=0. Then you further factored t^2-1 as (t-1)(t+1) using the difference of squares formula. Finally, you set each factor equal to zero to find the values of t that make the equation true. So, the solutions to the equation are t=0 and t=1, which can be written as {0,1}.