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Algebra 2

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Is this how you solve t^3 - t = 0?

t(t^2-1)=0
t(t-1)(t-1)=0
t=0 or t=1
{0,1}

  • Algebra 2 -

    no, t(t+1)(t-1)=0
    now solve.

  • Algebra 2 -

    so t=0 or t=-1 or t=1, and the solution set is {0,-1,1}?

  • Algebra 2 -

    yes.

  • Algebra 2 -

    thanks

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