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September 22, 2014

September 22, 2014

Posted by **Jamie** on Tuesday, September 28, 2010 at 8:12pm.

I think the answer is secθ but I don't know how to get this.

2.) (tanθ) / (cos)(90° -θ)

3.) 3sin2xcos2x - sin4x

4.) (cosx + tanx) / (csc^2 x)

- Math- Simplifying Identities -
**Reiny**, Tuesday, September 28, 2010 at 8:37pmcot(-θ)(secθ)

= cos(-Ø)/sin(-Ø)(1/cosØ

= (cosØ/-sinØ)(1/cosØ

= - 1/sinØ

= - csc(Ø)

(test your answers with some weird angle, don't use 30's , 60's, or 45's)

2. you will have to know that

cos(90°-x) = sinx

take it from there

3. 3sin2xcos2x - sin4x

= 3sin2xcos2x - 2sin2xcos2x

= sin2xcos2x

or (1/2)sin4x

4. change everything to sines and cosines and just mess around with it.

make sure to test your answer vs the original with some strange angle on your calculator.

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