Posted by Jamie on Tuesday, September 28, 2010 at 8:12pm.
I think the answer is secθ but I don't know how to get this.
2.) (tanθ) / (cos)(90° -θ)
3.) 3sin2xcos2x - sin4x
4.) (cosx + tanx) / (csc^2 x)
- Math- Simplifying Identities - Reiny, Tuesday, September 28, 2010 at 8:37pm
= - 1/sinØ
= - csc(Ø)
(test your answers with some weird angle, don't use 30's , 60's, or 45's)
2. you will have to know that
cos(90°-x) = sinx
take it from there
3. 3sin2xcos2x - sin4x
= 3sin2xcos2x - 2sin2xcos2x
4. change everything to sines and cosines and just mess around with it.
make sure to test your answer vs the original with some strange angle on your calculator.
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