Calculate the molarity of a solution made by dissolving 0.0715 mol Na2SO4 in enough water to form 550 mL of solution.

While we're at it...

How many milliliters of 10.6 M HCl solution are needed to obtain 0.205 mol of HCl?

Also...

How many grams of solute are present in 50.0 mL of 1.33 M CoSO4?

In conclusion...

If 4.50 g of (NH4)2SO4 is dissolved in enough water to form 250. mL of solution, what is the molarity of the solution?

For #1, the definition is

M = mols/L of solution. Substitute and you have it.

what molarity does a solution with 17.1 grams of sugar and 500 mL of distilled water have?

To calculate the molarity of a solution, you need to use the formula:

Molarity (M) = moles of solute / volume of solution (in liters)

Let's calculate the molarity for each of the given questions:

1. Molarity of Na2SO4 solution:
Moles of Na2SO4 = 0.0715 mol
Volume of solution = 550 mL = 550 / 1000 = 0.55 L

Molarity (M) = 0.0715 mol / 0.55 L = 0.130 M

2. Volume of HCl solution:
Moles of HCl = 0.205 mol
Molarity of HCl solution = 10.6 M

Using the molarity formula, we can rearrange it to solve for volume:
Volume of HCl solution (L) = moles of HCl / Molarity of HCl solution
Volume of HCl solution = 0.205 mol / 10.6 M

Convert mL to L (since the molarity formula requires volume in liters):
Volume of HCl solution = (0.205 mol / 10.6 mol/L) * 1000 mL / L = 19.34 mL

Therefore, you would need 19.34 mL of 10.6 M HCl solution.

3. Grams of CoSO4 present:
Volume of CoSO4 solution = 50.0 mL = 50.0 / 1000 = 0.050 L
Molarity of CoSO4 solution = 1.33 M

Using the molarity formula, we can rearrange it to solve for moles:
Moles of CoSO4 = Molarity of CoSO4 solution * Volume of CoSO4 solution
Moles of CoSO4 = 1.33 mol/L * 0.050 L

Now, we can calculate the grams of CoSO4 using its molar mass, which is:
CoSO4 molar mass = 58.9334 g/mol + 32.065 g/mol + 4 * 15.9994 g/mol = 172.984 g/mol

Grams of CoSO4 = Moles of CoSO4 * CoSO4 molar mass
Grams of CoSO4 = 1.33 mol/L * 0.050 L * 172.984 g/mol

Hence, there are 4.48 g of CoSO4 present in 50.0 mL of 1.33 M CoSO4 solution.

4. Molarity of (NH4)2SO4 solution:
Mass of (NH4)2SO4 = 4.50 g
Volume of solution = 250 mL = 250 / 1000 = 0.250 L

First, calculate the moles of (NH4)2SO4:
Moles of (NH4)2SO4 = mass of (NH4)2SO4 / molar mass of (NH4)2SO4
Molar mass of (NH4)2SO4 = 2 * (14.0067 g/mol) + 4 * (1.00784 + 15.9994 g/mol)
Moles of (NH4)2SO4 = 4.50 g / 132.139 g/mol

Now, use the molarity formula to calculate the molarity:
Molarity (M) = Moles of (NH4)2SO4 / Volume of solution
Molarity (M) = (4.50 g / 132.139 g/mol) / 0.250 L

Thus, the molarity of the (NH4)2SO4 solution is 0.136 M.