Posted by **Amy~** on Tuesday, September 28, 2010 at 5:35pm.

For this inequality

3x^(2) - 2x -1 > or equal 0

I get x=1 , x=-1/3

would the solution set become

{x|1 < x < -1/3}

I wasn't sure about the sign, if it should be greater than or equal to .

- Math -
**Henry**, Tuesday, September 28, 2010 at 8:09pm
3x^2 - 2x - 1 >= 0,

Factor using the A*C Method:

A * C = 3 * -1 = -3 = 1 * -3,

3x^2 + (x -3x) - 1 >= 0,

(3x^2 - 3x) + (x - 1) >= 0,

3x(x - 1) + (x - 1) >= 0,

(x - 1) (3x + 1) >= 0,

x - 1 >= 0,

x >= 1.

3x + 1 >= 0,

3x >= -1,

x >= -1/3.

Solution Set: x >= 1, and x >= -1/3.

This is not a compound inequality; therefore, your last step does

not apply.

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