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Posted by on Tuesday, September 28, 2010 at 4:26pm.

Determine the zeros of the function 3x^2 -8=10x. I know I rewrite it as 3x^2 -10x-8 = 0

But then what do I do-I'm totally confused-Answers are
{-2,4}
{2,4}
{-2/3,4}
{2/3,4}
Please direct me or show the steps, just don't give me the answer because I still won't get it.I think it is -2/3,4 but I'm not sure-even if that is correct, please show me the steps.
Thank you

  • Math - , Tuesday, September 28, 2010 at 5:37pm

    I would factor it.
    (3x+2)(x-4)=0

    x= -2/3, or x=4

  • Math - , Tuesday, September 28, 2010 at 6:09pm

    3x^2 - 10x - 8 = 0,
    Factor using the A*C Method:
    A * C = 3 * -8 = -24 = 2 * -12,
    3x^2 + (2x - 12x) - 8 = 0.

    Group the 4 terms into factorable pairs:
    (3x^2 - 12x) + (2x - 8) = 0,
    3x(x - 4) + 2(x - 4) = 0,
    Factor (x - 4) from each term:
    (x - 4) (3x + 2) = 0,
    x - 4 = 0,
    x = 4.

    3x + 2 = 0,
    3x = -2,
    x = -2/3.

    Solution set: x =-2/3, and x = 4.

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