Determine the zeros of the function 3x^2 -8=10x. I know I rewrite it as 3x^2 -10x-8 = 0

But then what do I do-I'm totally confused-Answers are
{-2,4}
{2,4}
{-2/3,4}
{2/3,4}
Please direct me or show the steps, just don't give me the answer because I still won't get it.I think it is -2/3,4 but I'm not sure-even if that is correct, please show me the steps.
Thank you

I would factor it.

(3x+2)(x-4)=0

x= -2/3, or x=4

3x^2 - 10x - 8 = 0,

Factor using the A*C Method:
A * C = 3 * -8 = -24 = 2 * -12,
3x^2 + (2x - 12x) - 8 = 0.

Group the 4 terms into factorable pairs:
(3x^2 - 12x) + (2x - 8) = 0,
3x(x - 4) + 2(x - 4) = 0,
Factor (x - 4) from each term:
(x - 4) (3x + 2) = 0,
x - 4 = 0,
x = 4.

3x + 2 = 0,
3x = -2,
x = -2/3.

Solution set: x =-2/3, and x = 4.

To determine the zeros of the function 3x^2 - 10x - 8 = 0, you can use the quadratic formula. The quadratic formula states that for a quadratic equation in the form ax^2 + bx + c = 0, the solutions for x are given by:

x = (-b ± √(b^2 - 4ac)) / (2a)

In your equation, a = 3, b = -10, and c = -8. Plugging these values into the quadratic formula, we get:

x = (-(-10) ± √((-10)^2 - 4 * 3 * (-8))) / (2 * 3)
= (10 ± √(100 + 96)) / 6
= (10 ± √196) / 6
= (10 ± 14) / 6

Now we have two possible solutions:
1) When x = (10 + 14) / 6 = 24 / 6 = 4
2) When x = (10 - 14) / 6 = -4 / 6 = -2/3

So, the zeros of the function 3x^2 - 10x - 8 = 0 are {4, -2/3}. Hence, the correct answer is {4, -2/3}.