Posted by **Beth Anne** on Tuesday, September 28, 2010 at 4:26pm.

Determine the zeros of the function 3x^2 -8=10x. I know I rewrite it as 3x^2 -10x-8 = 0

But then what do I do-I'm totally confused-Answers are

{-2,4}

{2,4}

{-2/3,4}

{2/3,4}

Please direct me or show the steps, just don't give me the answer because I still won't get it.I think it is -2/3,4 but I'm not sure-even if that is correct, please show me the steps.

Thank you

- Math -
**bobpursley**, Tuesday, September 28, 2010 at 5:37pm
I would factor it.

(3x+2)(x-4)=0

x= -2/3, or x=4

- Math -
**Henry**, Tuesday, September 28, 2010 at 6:09pm
3x^2 - 10x - 8 = 0,

Factor using the A*C Method:

A * C = 3 * -8 = -24 = 2 * -12,

3x^2 + (2x - 12x) - 8 = 0.

Group the 4 terms into factorable pairs:

(3x^2 - 12x) + (2x - 8) = 0,

3x(x - 4) + 2(x - 4) = 0,

Factor (x - 4) from each term:

(x - 4) (3x + 2) = 0,

x - 4 = 0,

x = 4.

3x + 2 = 0,

3x = -2,

x = -2/3.

Solution set: x =-2/3, and x = 4.

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