Posted by **BethAnne** on Tuesday, September 28, 2010 at 1:36pm.

Determine the zeros of the function 3x^2 -8=10x. I know I rewrite it as 3x^2 -10x-8 = 0

But then what do I do-I'm totally confused-Answers are

{-2,4}

{2,4}

{-2/3,4}

{2/3,4}

Please direct me or show the steps, just don't give me the answer because I still won't get it.

Thank you

- Algebra -
**PsyDAG**, Wednesday, September 29, 2010 at 12:04pm
What factors does 8 have (8,1 or 4,2?) that, when one is multiplied by 3, will add/subtract to get -10?

4*3 = 12, when you subtract 2 from that product, that give you 10. Just make sure you get the signs right.

(3x+2)(x-4) = 0

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