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January 30, 2015

January 30, 2015

Posted by **jam** on Tuesday, September 28, 2010 at 1:02pm.

2a+squareroot of 2a^2=10

- math subject -
**Henry**, Thursday, September 30, 2010 at 4:58pm2a + sqrt(2a^2) = 10,

Isolate the radical:

2a - 10 = -sqrt(2a^2),

Square both sides:

4a^2 - 40a + 100 = 2a^2,

4a^2 - 2a^2 - 40a + 100 = 0,

2a^2 - 40a + 100 = 0,

Divide both sides by 2:

a^2 - 20a + 50 = 0,

Solve for a using the quadratic formula:

a = (20 +- sqrt(400 - 200) / 2,

(20 +- sqrt(100 * 2) / 2,

a = (20 +- 10 * sqrt(2)) / 2,

a = 10 +- 5 * sqrt(2),

a = 10 +- 7.07,

a = 17,07, and 2.93.

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