Thursday

September 29, 2016
Posted by **Sarah** on Tuesday, September 28, 2010 at 12:28pm.

The mother replies, "I have no one-year-olds. The product of my

children's ages is 90, and the sum of their ages is the same as my

house number."

The census taker replies. "I can see the house number but I still need

more information."

The mother says, "You're right. You also need to know that the boy

across the street is older than my oldest child."

The census taker says, "Thank you, I now know the ages of your

children."

What are the ages of the children?

What is the house number?

What is the age of the boy across the street?

I made a list of factors, but don't know where to go from there. Thank you for your help!

- Math -
**MathMate**, Tuesday, September 28, 2010 at 4:24pmCan you post the list of factors that you have made?

- Math -
**MathMate**, Tuesday, September 28, 2010 at 9:06pmI feel like I'm missing information, but here's the best I can do.

Product of ages = 90

Prime factors of 90: 2,3,3,5

So the possible number and age of children are:

2,3,3(twins),5

3,5,6

2,5,9

3,3(twins),10

2,3,15

6,15

5,18

Since the mother said "...older than my old**est**child.", there must be three or more children, or even three different ages. That leaves us with:

2,3,3(twins),5

3,5,6

2,5,9

2,3,15

Some cities do not put 13 as a house number, so we eliminate the first case, to leave us with:

3,5,6 (sum=14)

2,5,9 (sum=16)

2,3,15 (sum=20)

If we eliminate ages that are too close, one year apart (but logically & physically feasible), that leaves us only with 2,5,9 (sum=16).

Also, the boy across the street can be one or more years older than the oldest child.

If you have other hints/conclusions, please post.