-9+x = x/8 -23
multiply be 8x to get the quadratic
-72x + 8x^2 = x^2 - 184
7x^2 - 72x + 184 = 0
solve using the quad formula
Can you please explain what the quad formula is?
Ok, I meant
the Quadratic Equation Formula
ax^2 + bx + c = 0
x = (-b ± √(b^2-4ac))/(2a)
use place value blocks to model 5/10 and 67/100 write a decimal that shows the same amount What's the answer?
To solve the equation -9 + x = x/8 - 23, we need to first simplify and then solve for x. Here's how:
Step 1: Get rid of the fractions by multiplying the entire equation by 8 to clear the denominator. (Recall that multiplying both sides of an equation by the same non-zero number doesn't change its solution.)
8(-9 + x) = 8(x/8 - 23)
Now simplify:
-72 + 8x = x - 184
Step 2: Group the x terms together on one side of the equation and the constant terms on the other side. To do this, subtract x from both sides:
-72 + 8x - x = -184
Simplifying:
7x - 72 = -184
Step 3: Move the constant term (-72) to the other side by adding 72 to both sides:
7x - 72 + 72 = -184 + 72
Simplifying:
7x = -112
Step 4: Finally, solve for x by dividing both sides of the equation by 7:
(7x)/7 = -112/7
Simplifying:
x = -112/7
x = -16
Therefore, the solution to the equation -9 + x = x/8 - 23 is x = -16.