Monday

December 22, 2014

December 22, 2014

Posted by **Anna** on Monday, September 27, 2010 at 9:26pm.

f(x)=(x^3-2x^2+x+1)(sqrt(x)-3x+9)

I did:

f'(x)=[x^3-2x^2+x+1][(1/2x^(-1/2)-3]+[x^(1/2)-3x+9][3x^2-4x+1]

which I got to be

[-12x^3+(7/2)x^(5/2)+46x^2-5x^(3/2)-42x+(3/2)x^(1/2)+6]/[2x^(1/2)]

I just wanted to make sure I didn't make any mistakes because the fractions are confusing.

- calc -
**Reiny**, Monday, September 27, 2010 at 10:24pmYour first line derivative is correct, however, I haven't got a clue how you got that last line.

- calc -
**Anna**, Monday, September 27, 2010 at 10:29pmThats what I got whenever I simplified it

**Answer this Question**

**Related Questions**

Calculus - Find the outside and inside functions of the following to find their ...

Calculus - Using the derivative definition of f ‘ (x) = (f (x+h) – f (x)) / (h) ...

calc - find the derivatives of the given functions. g(t)=sqrt t(1+t)/t^2

calculus - (derivatives) - Find the derivative of the function f by using the ...

Calc I - Find the range of y = (3x-1)/(2x^2 + x - 6) I was going to take the ...

Calculus - find the derivatives of the given functions. g(t)=sqrt t(1+t)/t^2 ...

calculus help - Is there any good calculus websites out there that teach every ...

Check my CALCULUS answers please! - Any short explanation for things I got ...

algebra,math,help - Use Property 2 to simplify each of the following radical ...

calculus - derivatives - can you please find the first 5 derivatives for: f(x...