Please help with these 2 stoichiometry questions.
How many grams of NH3 can be produced from 3.98 mol of N2?
How many grams of H2 are needed to produce 10.41g of NH3?
Here is the process for working stoichiometry problems. You already have moles so you can skip step 2.
http://www.jiskha.com/science/chemistry/stoichiometry.html
How many of CaOare needed to react with excess water to produce 370g of calcium hydroxide?
To solve stoichiometry questions like these, we need to follow a series of steps. Let's start with the first question:
1. Write a balanced chemical equation: The balanced equation for the reaction between N2 and NH3 is:
N2 + 3H2 -> 2NH3
2. Determine the molar ratio: From the balanced equation, we can see that 1 mol of N2 reacts with 2 mol of NH3. Therefore, the molar ratio between N2 and NH3 is 1:2.
3. Convert moles to grams: Since we have the number of moles of N2, we need to convert it to grams using the molar mass of N2, which is approximately 28.02 g/mol.
grams of N2 = moles of N2 * molar mass of N2
= 3.98 mol * 28.02 g/mol
≈ 111.4996 g
4. Use the molar ratio to find the grams of NH3 produced: Since the molar ratio tells us that 1 mol of N2 produces 2 mol of NH3, we can set up a ratio to find the grams of NH3.
grams of NH3 = grams of N2 * (2 mol of NH3 / 1 mol of N2)
= 111.4996 g * (2 mol/1 mol)
≈ 222.9992 g
Therefore, approximately 222.9992 grams of NH3 can be produced from 3.98 mol of N2.
Now, let's move on to the second question:
1. Write a balanced chemical equation: We already have the balanced equation from the previous question: N2 + 3H2 -> 2NH3
2. Determine the molar ratio: From the balanced equation, we can see that 3 mol of H2 reacts with 2 mol of NH3. So, the molar ratio between H2 and NH3 is 3:2.
3. Convert grams of NH3 to moles: We start by converting the given mass of NH3 to moles using the molar mass of NH3, which is approximately 17.03 g/mol.
moles of NH3 = grams of NH3 / molar mass of NH3
= 10.41 g / 17.03 g/mol
≈ 0.611 mol
4. Use the molar ratio to find the grams of H2 needed: Since the molar ratio tells us that 3 mol of H2 produces 2 mol of NH3, we can set up a ratio to find the grams of H2.
grams of H2 = moles of NH3 * (3 mol of H2 / 2 mol of NH3)
= 0.611 mol * (3 mol/2 mol)
≈ 0.9165 g
Therefore, approximately 0.9165 grams of H2 are needed to produce 10.41 grams of NH3.