A horse is pulling a canal boat at 12 degrees to the rope. Tension of the rope it 1150 newtons. The canal is moving at a steady speed. Calculate the resistive forces opposing the boats forward motion.

Force forward= 1150*cos12

Since there is no acceleration, this pulling force must be equal to resistive force forward.

How did you get cos

just by putting cos(12) in calculator

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A horse is pulling a canal boat at 12 degrees to the rope. Tension of the rope it 1150 newtons. The canal is moving at a steady speed. Calculate the resistive forces opposing the boats forward motion.

physics (SAT 2) -

Well, well, well, looks like we have a horse who's a master at tug-of-war! Now, let's think about those resistive forces opposing the boat's forward motion.

The force of tension in the rope, which is 1150 newtons, can be resolved into two components: the horizontal component and the vertical component. The vertical component is counteracting the gravity, so it's not affecting the boat's forward motion.

But it's the horizontal component that's got a beef with the boat's progress. Since the rope is at an angle of 12 degrees, we need to find the horizontal component of the tension force.

To do that, we'll use a bit of trigonometry. Are you ready to put your math hat on? I'll wait while you find it...

Alright, let's continue. To find the horizontal component, we'll use the formula:

Horizontal component = Tension * cosine(angle)

Plugging in the numbers, we get:

Horizontal component = 1150 N * cos(12 degrees)

Now, let's do some magic with our calculators!

Calculating, calculating...

And voila! The horizontal component of the tension force is approximately 1130.58 newtons.

So, that means the resistive force opposing the boat's forward motion is also around 1130.58 newtons.

But hey, don't blame the boat for being resistant. It's just trying to keep things interesting on the canal!

To calculate the resistive forces opposing the boat's forward motion, we need to analyze the forces acting on the boat. In this case, the main force acting on the boat is the tension in the rope pulling it forward, and the resistive forces opposing its motion are the frictional forces.

First, let's break down the given information:
- The tension in the rope is 1150 newtons.
- The horse is pulling the canal boat at an angle of 12 degrees to the rope.

To find the resistive forces, we first need to determine the horizontal and vertical components of the tension force. We can use trigonometry to find these components.

The vertical component of the tension force can be calculated using the formula:
Vertical component = Tension force × sin(angle)

Vertical component = 1150 N × sin(12°) ≈ 238.55 N

Since the canal is moving at a steady speed, we know that the resistive forces opposing the boat's forward motion are equal to the horizontal component of the tension force. Therefore, the resistive forces can be calculated using the formula:
Resistive forces = Tension force × cos(angle)

Resistive forces = 1150 N × cos(12°) ≈ 1135.55 N

So, the resistive forces opposing the boat's forward motion are approximately 1135.55 newtons.