If 100.0 J are added to 20.0 grams of water at 30.0 degrees Celsius. What will be the final temperature?

see above.

To determine the final temperature, we need to use the formula for heat transfer:

Q = m * c * ΔT

Where:
- Q is the heat transfer (in Joules)
- m is the mass of the substance (in grams)
- c is the specific heat capacity of the substance (in J/g°C)
- ΔT is the change in temperature (in °C)

First, let's convert the mass of water from grams to kilograms:
20.0 grams = 0.020 kilograms

Next, we need to find the specific heat capacity of water. The specific heat capacity of water is approximately 4.18 J/g°C.

Now, let's rearrange the formula to solve for the change in temperature (ΔT):

ΔT = Q / (m * c)

Plugging in the values:
ΔT = 100.0 J / (0.020 kg * 4.18 J/g°C)

Calculating this gives us:
ΔT ≈ 119.62 °C

Lastly, to find the final temperature, we add the change in temperature (ΔT) to the initial temperature:
Final temperature = Initial temperature + ΔT
Final temperature = 30.0 °C + 119.62 °C

Calculating this gives us:
Final temperature ≈ 149.62 °C

Therefore, the final temperature will be approximately 149.62 °C.