Posted by Katie on Monday, September 27, 2010 at 2:48pm.
The horizontal distance does not change the time it takes to fall through the height of the cliff. It's there probably to throw you off, or there's a second part of the question.
What is important is the initial velocity is horizontal, so the vertical component, u, is zero.
vertical drop
S = ut+(1/2)gt²
= 0 + (1/2)(9.8)*2.6²
=?
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