Posted by Katie on Monday, September 27, 2010 at 2:48pm.
A diver running 2.4 m/s dives out horizontally from the edge of a vertical cliff and 2.6 s later reaches the water below. How high was the cliff?

physics  MathMate, Monday, September 27, 2010 at 4:19pm
The horizontal distance does not change the time it takes to fall through the height of the cliff. It's there probably to throw you off, or there's a second part of the question.
What is important is the initial velocity is horizontal, so the vertical component, u, is zero.
vertical drop
S = ut+(1/2)gt²
= 0 + (1/2)(9.8)*2.6²
=?

physics  Anonymous, Monday, September 15, 2014 at 9:03pm
0.72
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