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March 29, 2017

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A diver running 2.4 m/s dives out horizontally from the edge of a vertical cliff and 2.6 s later reaches the water below. How high was the cliff?

  • physics - ,

    The horizontal distance does not change the time it takes to fall through the height of the cliff. It's there probably to throw you off, or there's a second part of the question.

    What is important is the initial velocity is horizontal, so the vertical component, u, is zero.

    vertical drop
    S = ut+(1/2)gt²
    = 0 + (1/2)(9.8)*2.6²
    =?

  • physics - ,

    0.72

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