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October 30, 2014

October 30, 2014

Posted by **Katie** on Monday, September 27, 2010 at 2:48pm.

- physics -
**MathMate**, Monday, September 27, 2010 at 4:19pmThe horizontal distance does not change the time it takes to fall through the height of the cliff. It's there probably to throw you off, or there's a second part of the question.

What is important is the initial velocity is horizontal, so the vertical component, u, is zero.

vertical drop

S = ut+(1/2)gt²

= 0 + (1/2)(9.8)*2.6²

=?

- physics -
**Anonymous**, Monday, September 15, 2014 at 9:03pm0.72

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