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April 1, 2015

April 1, 2015

Posted by **karla** on Monday, September 27, 2010 at 12:42pm.

a) With what speed did the ball bearing leave the slingshot?

b) What was the ball's velocity just before it hit the ground?

- physics -
**MathMate**, Monday, September 27, 2010 at 3:40pma)

Time to reach highest point = 3.2/2=1.6s

0=u-gt

Initial velocity, u=9.8*1.6=?

b)

On its way down, the velocity is -u at the top of the building, and v on the ground. Acceleration is still -9.8 m/s².

Use

v²-u²=2aS

a=-9.8 m/s²

S=-48m

u= calculated above

Solve for v.

For b)

you could also use energy,

(1/2)mv²-(1/2)mu²=mgh

h=48m.

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