Posted by sahan on Monday, September 27, 2010 at 12:34am.
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First, quantify the given data in terms of symbols:
Length of inclined plane, S = 1.6m
inclination, θ =25°
mass of block, m = 2.5 kg
Initial velocity, u = 0 m/s
Final velocity, v = 0.65 m/s
acceleration = a m/s² (along incline)
coefficient of kinetic friction = μ
Look up your class notes or textbook and be familiar with the formulas required in kinematics of uniform accelerations, and inclined planes.
The approach could be:
1. calculate the net acceleration using the formula
2aS = v²-u²
2. Draw a free body diagram of the block, indication the direction and magnitude of the following forces:
weight due to gravity = mg (downwards)
Normal component of weight = mg*cos(θ) normal to inclined plane
downward component of weight F2= mg*sin(θ) (parallel to inclined plane, downwards)
frictional resistance, Fk= μN (in direction opposite to F2)
Therefore F=F2-Fk is the net force causing the calculated acceleration.
By equating F=ma, μ can be solved for.
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