Posted by KELLY on Sunday, September 26, 2010 at 11:14pm.
Write the equation and balance it.
mols AgNO3 = M x L
mols K2SO4 = M x L
Determine the limiting reagent. I think K2SO4 is limiting but check me out on that. If so then AgNO3 is a common ion to the ppt of Ag2SO4.
Ag^+ in the final solution, then, is Ag^+ from unused AgNO3 (subtract moles AgNO3 initially - 2(moles K2SO4) = unused AgNO3). That will be the moles of Ag^+ from the unused AgNO3 and you can change that to molarity by M = moles/L. Ag2SO4 is not extremely soluble but it is somewhat soluble. Look up the Ksp of Ag2SO4 and calculate Ag^+ from that, then add to the unused AgNO3. I think the amount from Ag2SO4 is so small that you can ignore that but you may want to check me out on that, too.
Related Questions
chemistry - 0.550g sample containing only nacl and kbr.it dissolved in water and...
chemistry - The Ksp for silver sulfate (Ag2SO4) is 1.2 10-5. Calculate the ...
CHEMISTRY - 1. You have 88.8 mL of 2.50 M solution of Na2CrO4 (aq). You have 125...
Chemistry - you have75.0ml of 2.5 M Solution of Na2CrO4(aq). You also have ...
Chem 22 - molecular equation, and net ionic equation of K2SO4 + MgCl2 NiCl2 + ...
Chemistry - Which two solutions, when mixed together, will undergo a double ...
chemistry - By means of what single reagent could you distinguish between the ...
Chemistry - Hi! I kind of need help to get started with these four problems. ...
chemistry - Determine whether a solid forms when solutions containing the follow...
Chemistry - Calculate the volume (in mL) of 9.0M H2SO4 that you would need to ...
For Further Reading
