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March 3, 2015

March 3, 2015

Posted by **Carol** on Sunday, September 26, 2010 at 7:43pm.

- physics -
**Henry**, Monday, September 27, 2010 at 6:01pmSince no starting point was given, I assumed the trip started at the Origin.

Therefore, we'll subtract 0 from the vector sum to get the displacement.

Southwest = 45 deg. west of South = 225 deg CCW from 0 deg.

X = Hor. = -165 + 165*cos225,

X = -165 + -17.7 = -182.7 km,

Y = Ver. = 25*sin225 = -17.7 km.

tanA = 17.7 / 182.7 = 0.0969,

A = 5.53 deg,

D = 182.7 + i17.7,

D = 182.7 / cos5.53 = 183.6 km @

5.53 deg South of West.

D = 182.7 +i17.7,

- physics -
**Henry**, Monday, September 27, 2010 at 6:09pmCORRECTION!

X = Hor. = -165 + 25*cos225.

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