Posted by **Randy** on Sunday, September 26, 2010 at 6:53pm.

Assume that about 45% of all U.S. adults try to pad their insurance claims. Suppose that you are the director of an insurance adjustment office. Your office has just received 110 insurance claims to be processed in the next few days. What is the probability that fewer than 45 of the claims have been padded?

- statistics -
**MathGuru**, Monday, September 27, 2010 at 4:49pm
Your values are the following:

p = .45, q = 1 - p = .55, x = 45, and n = 110

Use the normal approximation to the binomial distribution.

Find mean and standard deviation.

mean = np = (100)(.45) = ?

sd = √npq = √(100)(.45)(.55) = ?

Once you determine the mean and standard deviation, use z-scores and z-table to find probability:

z = (x - mean)/sd

Substitute the values into the formula. Once you have the z-score, determine your probability using a z-table.

I hope this will help get you started.

- statistics -
**MathGuru**, Monday, September 27, 2010 at 4:52pm
Correction:

Use 110 for n.

## Answer this Question

## Related Questions

- Statistics - Assume that about 45% of all U.S. adults try to pad their insurance...
- Statistics - Assume that about 45% of all U.S. adults try to pad their insurance...
- Statistics - Assume that about 45% of all U.S. adults try to pad their ...
- Statistics - Assume that about 45% of all U.S. adults try to pad their insurance...
- Statistics - Assume that about 45% of all U.S. adults try to pad their insurance...
- Statistics - Assume that about 45% of all U.S. adults try to pad their insurance...
- statistics - According to the book Are you Normal?,40% of all US adults try to ...
- statistics - According to the book Are you Normal?,40% of all US adults try to ...
- statistics - According to the book Are yoy Normal?, 40% of all US adults try to ...
- Health care - Please check my anser thank you :) You work in a doctor's office ...