What is the domain of (sec(x)-1)/(x^2)?
Math - MathMate, Sunday, September 26, 2010 at 8:25pm
The domain of a function
f(x)=g(x)/h(x) is given by
which means to find the domain of f(x), we calculate the intersection of the domains of g(x) and h(x), less the points at which h(x)=0 (vertical asymptotes).
In your case,
dom(sec(x)-1) is ℝ,
dom(x²) is also ℝ
All you need to do is to find
dom(sec(x)-1) ∩ dom(x²) but exclude points at which x²=0.