Post a New Question


posted by on .

What is the freezing point (°C) of a solution prepared by dissolving 11.3 g of Ca(NO3)2
(formula weight = 164 g/mol) in 115 g of water? The molal freezing point depression constant for
water is 1.86 °C/m.

whats wrong with my answer:

molal: 0.069 moles Ca(NO3)2/0.115kg= 0.6
but its wrong, the answer is supposed to be -3.34

  • chem - ,

    You forgot that Ca(NO3)2 ionizes into three ions so the van't Hoff factor is 3.
    delta T = i*Kf*m
    So multiply your answer by 3 and you'll have it.

  • chem - ,

    why is it negative?

  • chem - ,

    bc adding solute to soln decreases the freezing pt.

Answer This Question

First Name:
School Subject:

Related Questions

More Related Questions

Post a New Question