Posted by
**jessie** on
.

What is the freezing point (°C) of a solution prepared by dissolving 11.3 g of Ca(NO3)2

(formula weight = 164 g/mol) in 115 g of water? The molal freezing point depression constant for

water is 1.86 °C/m.

whats wrong with my answer:

molal: 0.069 moles Ca(NO3)2/0.115kg= 0.6

0.6x1.86=1.116

but its wrong, the answer is supposed to be -3.34