Calculate the final temp. of 100g of Ag at 40 C is immersed in 60.0g of water at 10.0 C.
SH of Ag is 0.065 cal/g/C
SH of H2O is 4.184 J/g/C
I can't figure out how to put delta T in the equation when I haven't found it yet :-\
[mass Ag x SH Ag x (Tfinal-Tinitial)] + [mass water x SH water x (Tfinal-Tinitial)] = 0
Tfinal is the only unknown.Ag will be at the final T and water will be at the same final T.
